(2x^2-x-3)+(x+1)=y

Solution for (2x^2-x-3)+(x+1)=y equation:

Simplifying
(2x2 + -1x + -3) + (x + 1) = y

Reorder the terms:
(-3 + -1x + 2x2) + (x + 1) = y

Remove parenthesis around (-3 + -1x + 2x2)
-3 + -1x + 2x2 + (x + 1) = y

Reorder the terms:
-3 + -1x + 2x2 + (1 + x) = y

Remove parenthesis around (1 + x)
-3 + -1x + 2x2 + 1 + x = y

Reorder the terms:
-3 + 1 + -1x + x + 2x2 = y

Combine like terms: -3 + 1 = -2
-2 + -1x + x + 2x2 = y

Combine like terms: -1x + x = 0
-2 + 0 + 2x2 = y
-2 + 2x2 = y

Solving
-2 + 2x2 = y

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '2' to each side of the equation.
-2 + 2 + 2x2 = 2 + y

Combine like terms: -2 + 2 = 0
0 + 2x2 = 2 + y
2x2 = 2 + y

Divide each side by '2'.
x2 = 1 + 0.5y

Simplifying
x2 = 1 + 0.5y

Reorder the terms:
-1 + x2 + -0.5y = 1 + 0.5y + -1 + -0.5y

Reorder the terms:
-1 + x2 + -0.5y = 1 + -1 + 0.5y + -0.5y

Combine like terms: 1 + -1 = 0
-1 + x2 + -0.5y = 0 + 0.5y + -0.5y
-1 + x2 + -0.5y = 0.5y + -0.5y

Combine like terms: 0.5y + -0.5y = 0.0
-1 + x2 + -0.5y = 0.0

The solution to this equation could not be determined.